Doctor Strange comic con poster banner

It has already been confirmed that Benedict Cumberbatch‘s Doctor Strange‘s next Marvel Cinematic Universe appearance will be in ‘Thor: Raganrok’.

At the end of ‘Thor: The Dark World’, Loki (Tom Hiddleston) had ascended to the throne of Asgard thanks to his magical trickery.  with M

“Doctor Strange has intensely cerebral time-bending powers. At the end of Thor: The Dark World, Loki’s on the throne…what happened to Odin? So, maybe Doctor Strange has to help out with that particular conundrum.”

Using his illusion powers, Loki was impersonating Odin at the end of ‘Ragnarok’.  But what happened to the real Odin?  Is he still alive?  Surely this will be among the questions answered in this sequel, which we know will also set the stage for ‘Avengers: Infinity War’, in which Cumberbatch is also confirmed to appear.

In the post-credit scene in ‘Doctor Strange’ we saw both Thor and Loki searching for Odin, which seems to indicate that even he doesn’t know what became of the God King, but we know that Anthony Hopkins is returning in ‘Ragnarok’.

Hiddleston specifically mentions that Doctor Strange’s powers are “time-bending,” which may indicate that the heroes will be going backward in time to get some of their answers.

Watch Hiddleston’s post-Golden Globes interview with MTV below, which also includes hints about his upcoming movie ‘Kong: Skull Island’:

Of course, Cumberbatch will join not just Hiddleston and Chris Hemsworth’s Thor, but Mark Ruffalo as Bruce Banner/The Hulk, as the film takes place roughly concurrently with ‘Captain America: Civil War’.  (Tiny clues in ‘Doctor Strange’ indicate that that movie took place before ‘Avengers: Age of Ultron’.)

‘Thor: Ragnarok’, directed by Taika  Waititi, also stars Idris Elba as Heimdall and Jamie Alexander as Sif, as well as newcomers Cate Blanchett as Hela, Tessa Thompson as Valkyrie, Karl Urban as Skurge, Jeff Goldblum as the Grandmaster and Sam Neill in an undisclosed role.

Are you excited to see Cumberbatch in ‘Thor: Ragnarok’?